WebEvaluate the following using suitable identity. (105) 2 A 10025 B 11025 C 11125 D 12025 Medium Solution Verified by Toppr Correct option is B) (105) 2=(100+5) 2=100 2+5 2+2(100)(5) =10000+25+1000=11025 Was this answer helpful? 0 0 Similar questions Evaluate the following by using the identities: 103 2 Easy View solution > WebMar 31, 2024 · Transcript Ex 9.5, 6 Using identities, evaluate. (ix) 1.05×9.5 1.05×9.5 = 105/100×95/10 = (105 × 95)/1000 = ( (100 + 5) × (100 − 5))/1000 (𝑎+𝑏) (𝑎−𝑏)=𝑎^2−𝑏^2 Putting 𝑎 = 100 & 𝑏 = 5 = ( (100)^2 − (5)^2)/1000 = (10000 − 25)/1000 = 9975/1000 = 9.975 Next: Ex 9.5, 7 (i) → Ask a doubt Chapter 9 Class 8 Algebraic Expressions and Identities
Q126 Evaluate (105)^3 using a suitable Identity - YouTube
WebMar 21, 2024 · Q126 Evaluate (105)^3 using a suitable Identity Evaluate 105 3 Evaluate 105 whole cube - YouTube More Questions on Algebraic... WebExpand using suitable identity- 108×105 Easy Solution Verified by Toppr 108×105=(100+8)(100+5)=100 2+100(8+5)+8×5=10000+1300+40=11340 Was this answer helpful? 0 0 Similar questions Factorize the following using the Identities: x 2−64 Easy View solution > Factorize the following using the Identities: 49m 2−56m+16 Easy View … boundary dog park taplow
Evaluate using suitable identity a) 104 x 105 b) (98) 3
WebFind the following product by using suitable identity 102×104 A 10578 B 11508 C 10608 D 10218 Easy Solution Verified by Toppr Correct option is C) 102×104 =(100+2)×(100+4) Using, x 2+(a+b)x+ab =100 2+(2+4)100+2(4) =10000+600+8 =10608 Was this answer helpful? 0 0 Similar questions Find the product, using suitable properties … WebMar 24, 2024 · It is given that; \[{(105)^2}\] We have to evaluate the value of \[{(105)^2}\] by using suitable identity. With the help of the identities we can get any value quickly. An algebraic identity is an equality that holds for any values of its variables. \[105\] is close to 100. So, we can write it as \[105 = 100 + 5\] Now, we will apply the identity of WebSolution: Using algebraic Identities, (x + a) (x + b) = x 2 + (a + b)x + ab (a + b) (a - b) = a 2 - b 2 (i) 103 × 107 Identity: (x + a) (x + b) = x 2 + (a + b)x + ab 103 × 107 = (100 + 3) (100 + 7) Substituting x = 100, a = 3, b = 7 in the above identity, we get = (100) 2 + (3 + 7) (100) + (3) (7) = 10000 + 1000 + 21 = 11021 (ii) 95 × 96 gucci knock off purse